【答案】
解法1:桔子個(gè)數(shù)=2×蘋(píng)果個(gè)數(shù)(1)
桔子個(gè)數(shù)+蘋(píng)果個(gè)數(shù)=360(2)
把(1)代入(2)得:
2×蘋(píng)果個(gè)數(shù)+蘋(píng)果個(gè)數(shù)=360
即3×蘋(píng)果個(gè)數(shù)=360
∴蘋(píng)果個(gè)數(shù)=360÷3=120個(gè)
而桔子個(gè)數(shù)=2×120=240個(gè)
解法2:設(shè)桔子為x個(gè),蘋(píng)果為y個(gè),由題意列等式:
x=2y(1)
x+y=360(2)
把(1)代入(2)式得:2y+y=360即3y=360
得y=360÷3=120(個(gè))(蘋(píng)果)
而x=2y=2×120=240(個(gè))(桔子)



